if 7 times the 7th term of an ap is equal to 11 times its 11th term then find its 18th term
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Answer:
given:
7(a7)=11(a11)
7(a+6d)=11(a+10d)
7a+42d=11a+110d
-4a=68d
a=-68d/4
a18=a+17d
=(-68d/4) + 17d
=(-68d+68d)/4
=0/4
=0
hope it helps u....^_^
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