If 7 times the 7th term of an ap is equal to 11 times its 11th term then find its 18th term
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Answer:
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Answer:
→ a₁₈ = 0 .
Step-by-step explanation:
▶ Given :-
→ 7a₇ = 11a₁₁ .
▶ To find :-
→ a₁₈ .
Solution :-
We have,
⇒ 7a₇ = 11a₁₁ .
⇒ 7( a + 6d ) = 11( a + 10d ) .
⇒ 7a + 42d = 11a + 110d .
⇒ 11a - 7a = 42d - 110d .
⇒ 4a = - 68d .
⇒ 4a + 68d = 0 .
⇒ 4( a + 17d ) = 0 .
⇒ a + 17d = 0/4 .
⇒ a + ( 18 - 1 )d = 0.
∴ a₁₈ = 0 .
Hence, it is solved .
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