If 7 times the 7th term of an ap is equal to 11 times the 11 th term,then find its 18 th term
Answers
Answered by
9
7(a + (7-1)d) = 11(a + (11-1)d)
7a + 42d = 11a + 110d
4a + 68d = 0
a + 17d = 0
18th term = a + (18-1)d
= a + 17d
= 0
Answered by
5
Answer:
18th term=0
Step-by-step explanation:
t₇=a+6d
t₁₁=a+10d
According to question
7(a+6d)=11(a+10d)
7a+42d=11a+110d
-4a=68d
a=-17d
t₁₈=a+17d
=-17d+17d
=0
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