Question

If 7 times the 7th term of an ap is equal to 11th term of an ap, then find its 18th term

Answer 1

7(a₇) = a₁₁

7(a+6d)= a+10d

7a+42d = a+ 10d

7a-a = 10d - 42d

6a = -32d

a = -32d/6 = -16d / 3

a₁₈ = a+(n-1)d

     =  -16d/3 +(18-1)d

     = (-16d /3) +17d = (-16d +51d)/3 = 35d/3

Answer 2

$\underline{\bold{Answer:-}}$



Correction in the question :-

If seven times the 7th term of an AP is equal to eleven times the 11th term what will be its 18th term ?


For Solution

see the attachment









$\textbf{Hope it helps!}$