if 7 times the 7th term of an AP is equql to 11 times the 11th term of an AP then what will be the value of a18*a19
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Step-by-step explanation:
The 7th term is a₇ = a + 6d ----------(1)
The 11th term is a₁₁ = a + 10d ----------(2)
By condition,
7(a₇) = 11(a₁₁)
∴ 7(a + 6d) = 11(a + 10d)
7a + 42d = 11a + 110d
∴ -4a = 68d
∴ a = -17d
Substitue a in (1) and (2)
∴ a₇ = -17d + 6d = -11d
a₁₁ = -17d + 11d = -6d
Given a₁₈ x a₁₉:
a₁₈ = a + 17d = -17d + 17d = 0
a₁₉ = a + 18d = -17d + 18d = -d
a₁₈ x a₁₉ = 0 x -d = 0
∴ a₁₈ x a₁₉ = 0
Hope this helps!
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