Math, asked by riddhisps12, 5 months ago

If 7 upon 2 is one of tje roots equation 2x square-5x+k=0 then,k= ?

Answers

Answered by adarshsatishsingh333

2

2x²-5x+k=0 where x= 7/2

2×(7/2)²-5×7/2+k=0

= 49/2-35/2+k=0

14/2+k=0

k=-14/2

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