Question

If 7 worker complete their work in 16 days then how many days 4 worker complete the work?

Answer 1

Fᴏʀᴍᴜʟᴀ ᴜsᴇᴅ :-

➺ If M1 men can do W1 work in D1 days working H1 hours per day and M2 men can do W2 work in D2 days working H2 hours per day, then :-

❦❦ (M1*D1*H1)/W1 = (M2*D2*H2)/W2 ❦❦

Sᴏʟᴜᴛɪᴏɴ :-

Given That,

→ M1 = 7 workers

→ D1 = 16 Days.

→ M2 = 4 workers

→ D2 = x Days.

Putting all values in formula now, we get :-

→ 7 * 16 = 4 * x

Dividing both sides by 4,

→ 7 * 4 = x

→ x = 28 Days. (Ans.)

Hence, 4 workers complete same work in 28 Days..

Answer 2

$\huge{\tt{\pink{\: Question:-}}}$

If 7 worker complete their work in 16days ,then how many days 4 worker complete the work?

$\huge{\tt{\purple{\: Solution:-}}}$

$\star {\tt{\purple{\underline{Given:- }}}}$

M1 = 7 workers.

D1 = 16days.

M2 = 4 workers.

D2 = x

${\underline{\tt{Putting\:the\: values \: we \: get,}}}$

Now,

${\implies{\tt{7×16 = 4 × x}}}$

${\implies{\tt{\: or, \: x = \frac{7×16}{4}}}}$

$:\implies{\sf{ \frac {\cancel16×{7}}{\cancel{4}} = 28}}$

${\pink{\therefore{x =28}}}$

Therefore,4 workers completed the work in 28 days.