Question

If 7^x = 5^y = 175^z , prove that z = xy/2x+y

Answer 1

7^x=5^y=175^z=k (let); 7=k^1/x, 5=k^1/y, 175= k^1/z
7×5×5=175
K^1/x × k^1/y × k^1/y = k^1/z
1/x +1/h +1/h = 1/z
Z = xy/(2x+y)
Hence proved.