If 7(x² +x ) +k = 0 has equal roots, Find the value of k
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Answer:
k = 49/28
Step-by-step explanation:
7(x² +x ) +k = 0
7x²+7x+k = 0
a= 7, b= 7 and c= k
For equal roots, b²-4ac= 0
(7)²-4(7)(k) = 0
49 - 28k = 0
-28 k =- 49
k = 49/28
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