Question

. If 70% of a given radioactive sample is left un-decayed after 20 days, what is the % of original sample will get decayed in 60 days?

Answer 1

please mark the answer as brainliest......

and plzzz follow me......

Answer 2

34.4 % of original sample will get decayed in 60 days .

Given :

70% of a given radioactive sample is left un-decayed after 20 days .

We need to find the % of original sample will get decayed in 60 days .

We know ,

$N=N_oe^{-kt}$

Here , $N_o$ is initial number of sample .

Now ,

$0.7N_o=N_oe^{-kt}\\\\e^{-0.35}N_o=N_oe^{-kt}$

Comparing power of exponent we get :

$-k(20)=-0.35\\\\k=0.0178$

Therefore , equation becomes :

$N=N_oe^{-(0.0178)t}$

Putting t = 60 days

$N=N_oe^{-(0.0178)\times 60}\\\\N=N_oe^{-(0.0178)\times 60}\\\\N=N_o(0.344)$

Therefore , 34.4 % of original sample will get decayed in 60 days .

Hence , this is the required solution .

Learn More :

Decay

https://brainly.in/question/3187252