If 7128 = 2p × 3q × 11r , find the value of p+q+r
Answers
Answered by
10
Answer: 7
Step-by-step explanation:
7128 = 2 × 2 × 2 × 3 × 3 × 3 × 11
⇒ p = 3, q = 3 and r = 1
⇒ p + q + r = 3 + 3 + 1 = 7
Therefore, the value of p+q+r is 7
Hope it helps...
Mark as brainiest...
Answered by
3
Step-by-step explanation:
7128= 2^3 × 3^4 × 11^1
so p=3, q=4, r=1
therefore, p+q+r = 3+4+1 = 8 (ans).
Similar questions
Hindi,
1 month ago
Math,
1 month ago
Computer Science,
3 months ago
Computer Science,
9 months ago
Computer Science,
9 months ago