Question

If 7128 = 2p × 3q × 11r , find the value of p+q+r​

Answer 1

Answer:  7

Step-by-step explanation:

7128 = 2 × 2 × 2 × 3 × 3 × 3 × 11

⇒ p = 3,  q = 3  and  r = 1

⇒ p + q + r = 3 + 3 + 1 = 7

Therefore, the value of p+q+r is 7

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Answer 2

Step-by-step explanation:

7128= 2^3 × 3^4 × 11^1

so p=3, q=4, r=1

therefore, p+q+r = 3+4+1 = 8 (ans).