Question

If 7128 =2x. 3y. 11z, find (x + y + z)

Answer 1

Step-by-step explanation:

7138=(2)³+(3)⁴+(11)¹

Answer 2

Answer:

factorise 7128 first

7128= 2×2×2×3×3×3×3×11

therefore, 2 is three times , 3 is four times and 11 is one times so

x=3+y=4+z=1

x+y+z = 3+4+1

x+y+z = 8 answer