If 72 books weights 9 kg
(1) what is the weight of 80 such books?
(2) how many books weights 6 kg?
Answer please
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(1) 72/9=80/x=y/6
72/9=80/x
70x=80×9
x=80×9/72
x=10 kg
(2) 72/9=y/6
9y=72×6
y=72×6÷9
y=48 books
72/9=80/x
70x=80×9
x=80×9/72
x=10 kg
(2) 72/9=y/6
9y=72×6
y=72×6÷9
y=48 books
pickygazelle30:
its a case of direct proportion
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