Question

If 7cos2θ+ 3sin2 θ=4, then cot θ is…..​

Answer 1

Answer:

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$\sf\green{We, \: have\: 7cos² θ\: +\: 3sin² θ\: =\: 4}$

$\begin{gathered}\begin{gathered}\\ : \implies \displaystyle \sf \: 7(1−sin² θ)\: +\: 3sin² θ\: =\: 4\\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\\ : \implies \displaystyle \sf \: 4sin²θ\: =\: 3 \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\\ : \implies \displaystyle \sf \: sin²θ\: = \frac{3}{4} \: = \: ( [\frac{ \sqrt{3} }{2} )^{2} ] \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}\\ : \implies \displaystyle \sf \: \sin^{2} θ \: = \: \sin^{2} \frac{\pi}{3} \\ \\ \\\end{gathered}\end{gathered}$

$\begin{gathered}\begin{gathered}: \implies \underline{ \boxed{\displaystyle \sf \bold{\:θ \: = \: n\pi \: ±\: \frac{\pi}{3} nϵZ }} }\\ \\\end{gathered}\end{gathered}$

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Answer 2

Answer:

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