if 7cosec theta - 3cot theta = 7 , prove that 7cot theta-3cosec theta=3
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7cosec - 3cot =7
7cosec-7-3cot
7(cosec-1)=3cot
7(cosec-1)(cosec+1)=3cot(cosec+1)
7(cosec^2-1)=3cot(cosec+1)
7cot^2=3cot(cosec+1)
7cot 3(cosec+1)
7cot-3cosec+3
7cot-3cosec=3
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Answered by
3
7cosec - 3cot =7
7cosec-7-3cot
7(cosec-1)=3cot
7(cosec-1)(cosec+1)=3cot(cosec+1)
7(cosec^2-1)=3cot(cosec+1)
7cot^2=3cot(cosec+1)
7cot 3(cosec+1)
7cot-3cosec+3
7cot-3cosec=3
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