if 7cosecA-3cot=7 then prove that 7cot-3 cotA=3
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The given equation is, 7 cosec θ − 3 cot θ = 7squaring both sides, we get (7 cosec θ − 3 cot θ)2 = 49
⇒(7cosec θ)2 + (3cot θ)2 − 2(7cosec θ)(3cot θ) = 49
⇒49 cosec2θ + 9cot2θ − 42 cosec θ cot θ = 49
⇒49(1 + cot2θ) + 9(cosec2θ − 1) − 42 cosec θ cot θ = 49
⇒49 + 49cot2θ + 9cosec2θ − 9 − 42 cosec θ cot θ = 49
⇒ 49cot2θ + 9cosec2θ − 42 cosec θ cot θ = 9
⇒(7cot θ)2 + (3cosec θ)2 − 2(7cot θ)(3cosec θ) = 9
⇒(7 cot θ − 3 cosec θ)2 = 9
⇒(7 cot θ − 3 cosec θ) = 3
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