if 7sin^2 theta +3cos^2 theta =4 then prove that sec theta +cosec theta = 2 +2÷√3
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4Sin^2theta=1
and put in the L.H.S.
and put in the L.H.S.
MausamSingh:
let ABC be a triangle and C will be the angle therefore BC=squareroot of 3 and SECtheta=2/(squareroot of 3) and COSECtheta=2
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