Question

if 7sin^2A+3cos^2=4,show that tan A=1/√3​

Answer 1

Step-by-step explanation:

7sin²2A+3cos²2A=4

divid by cos²2A

7(sin²2A/cos²2A)+3(cos²2A/cos²2A)=4/cos²2A

7tan²2A+3=4sec²2A

we know that

sec²©-tan²©=1

so

7tan²2A+3=4(1+tan²2A)

7tan²2A+3=4+4tan²2A

3tan²2A=1

tan²2A=1/3

tan2A=1/√3

so

2A=30

A=15

so

tanA = tan15=2-√3

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Answer 2

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