If 7sin^2A+3cos^2A=4,find tanA
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7sin square thita +3cos square thita =4
4 sin square thita + 3sin square thita + 3cos square thita =4
4 sin square thita+3(sinsquarethita +cossquarethita)=4
4sin squre thita=1
sin thita=1/2
tan thita =1/root3
4 sin square thita + 3sin square thita + 3cos square thita =4
4 sin square thita+3(sinsquarethita +cossquarethita)=4
4sin squre thita=1
sin thita=1/2
tan thita =1/root3
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