Question

if 7sin^2ø+3cos^2ø=4 find the value √3tanø​

Answer 1

Answer:

Let ø = x.

$7 {sin}^{2}x + 3 {cos}^{2} x = 4 \\ 7 {sin}^{2} x + 3(1 - {sin}^{2} x) = 4 \\ 7 {sin}^{2} x + 3 - 3 {sin}^{2} x = 4 \\ 4 {sin}^{2} x = 1 \\ {sin}^{2} x = \frac{1}{4} \\ sinx = \frac{1}{2} \\ sinx = sin30 \\ x = 30$

$now \: \sqrt{3} tanx \\ = \sqrt{3} \times tan30 \\ = \sqrt{3} \times \frac{1}{ \sqrt{3} } \\ = 1$

Answer 2

Answer:

1 is answer..................