if 7sin sq.A + 3 cos sq.A = 4. Then evaluate tan A
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Answer:
given 7 sin² A + 3 cos² A = 4
to find A
7(1 - cos²A) + 3 cos² A = 4
7 - 7 cos²A + 3 cos² A = 4
3 cos²A - 7 cos²A = 4 -7
3 cos²A - 7 cos²A = -3
- 4 cos²A = - 3
4 cos²A = 3
cos²A = 3/4
cos A = √(3/4)
cos A = √3/2
cos A = cos 30°
therefore A = 30°
tan A = tan 30°
=> 1/√3
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