Question

if 7sin 'square' a + 3cos 'square' a =4 , then show that tan a =1/ root 3

Answer 1

Divide with cos^2a on both sides, we get

= 7 tan^2 a  + 3 = 4/cos^2 a    

= 7 tan^2 a + 3 = 4 sec^2 a

= 7 tan^2 a +3 = 4(1+tan^2 a)

= 7 tan^2 a +3 = 4 + 4 tan^2 a

= 3 tan^2 a = 1

= tan^2 a = 1/3

tan a = 1/ root 3


Hope this helps!

Answer 2

Answer:

Step-by-step explanation: