if 7sin2+3cos2=4,show that tan theta=1 by root4
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Plzz check that tan theta will be 1/√3
Hope it helps
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7 sin^2A + 3cos^2A=4
7sin^2A + 3cos^2A/cos^2 = 4/cos^2
7[sin^2A/cos^2] + 3[cos^2A/cos^2] = 4/cos^2
7tan^2A + 3 = 4sec^2A
7tan^2A + 3 = 4(1 + tan^2)
7 tan^2A + 3 = 4 +4tan^2
7tan^2A - 4tan^2A = 4 - 3
3tan^2A = 1
tan^2A= 1/3
tanA = 1/√3
hope this help you
7sin^2A + 3cos^2A/cos^2 = 4/cos^2
7[sin^2A/cos^2] + 3[cos^2A/cos^2] = 4/cos^2
7tan^2A + 3 = 4sec^2A
7tan^2A + 3 = 4(1 + tan^2)
7 tan^2A + 3 = 4 +4tan^2
7tan^2A - 4tan^2A = 4 - 3
3tan^2A = 1
tan^2A= 1/3
tanA = 1/√3
hope this help you
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