Question

If 7sin²∅ + 3cos²∅ = 4, then prove that sec∅ + cosec∅ = 2 + 2/√3

Answer 1

consider @ as theeta

4sin^2@+ 3sin^2 @ +3 cos^2@= 4

4 sin ^2@ +3 ( sin^2@+cos ^2@) =4

4sin^2 @+3 =4

4 sin^ 2 @ = 4 - 3

4sin ^ 2 @=1

sin^2@=1÷4

sin@=1/2

sin@ = sin 30

@ = 30

then sec @ + cosec @ =sec 30+cosec 30

2/ root 3 +2

hence proved

if u like my answer please mark me as brainliest