If 7sin2θ+3cos2θ=4 , then tanθ=
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Question:
If 7sin2θ+3cos2θ=4 , then tanθ=
Answer:
tanθ = ±√1/3
Step-by-step explanation:
Given => sin2θ+3cos2θ=4
To find => tanθ
Dividing both sides of the equation by cos2θ we have:
7tan2θ +3 = 4sec2θ = 4(1+tan2θ)
7tan2θ + 3 = 4 + 4tan2θ
⇒ 3tan2θ = 1
tanθ = ±√1/3
Hope you understand.
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