if 7sin²+3cos²A=4
then prove that tanA=1/√3
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Answer:
sinA2=1-cosA2
7(1-cosA2)+3cosA2=4
7-7cosA2+3cosA2=4
7-4cosA2=4
-4cosA2=- -3
cosA2=3/4
cosA=√3/4
cosA=√3/2
cosA=cos30
A=30
tanA=tan30
tan30=1/√3
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