Question

if 7sin²A+3cos²A=4,show that tanA=1/√3

Answer 1

Hey !!!

Solution ;- 7sin²¢ + 3cos²¢ = 4

•°• 7sin²¢ + 3cos²¢ /cos²¢ = 4 /cos²¢

=> 7tan²¢ + 3 = 4sec²¢

=> 7tan²¢ + 3 = 4( 1 +tan²¢ )

=> 7tan²¢ +3 = 4+4tan²¢

=> 7tan²¢ -4tan²¢ = 4-3

=> 3tan²¢ = 1

=> tan²¢ = 1/3..

=> tan = +-√1/3 Answer

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Hope it helps you !!!

#Rajukumar111▶

Answer 2

see this solution this could help