If 7sin²A+cos²A=44 Then show that taan=1÷3
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7sinA^2+cosA^2=44=> 6sinA^2+(sinA^2+cosA^2)=
44=> 6sinA^2=44-1=43=> sinA^2=43/6 .not possible as sinA ranges from -1to +1 .So no solution and invalid question .please change the question in the comments .
44=> 6sinA^2=44-1=43=> sinA^2=43/6 .not possible as sinA ranges from -1to +1 .So no solution and invalid question .please change the question in the comments .
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