Question

if 7sin²B + 3cos²B = 4(sin²B+cos²B) , then prove that CotB=√3
need fast answer please for today maths paper

Answer 1

Answer:

Step-by-step explanation:

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Answer 2

7sin^B+3cos^2B=4 (sin^2B+cos^2B)

7sin^2B+3cos^2B=4sin^2B+4cos^2B

7sin^2--4sin^2=4cos^2--3cos^2B

3sin^2B=cos^2B

(cosB/sinB)^2=3

cot^2B=3

$cotb = \sqrt{3}$