Question

if 7sin²ø+3cos²ø=4 then secø+cosecø is equal to??​

Answer 1

Step-by-step explanation:

Given, 7sin^2theta +3cos^2theta = 4

T.F => Sectheta+cosectheta

Solution:

7sin^2theta+3cos^2theta = 4

=> 7(1-cos^2theta) + 3cos^2theta = 4

or 7-7cos^2theta + 3cos^2theta = 4

or 3 =7cos^2-3cos^2theta

or 3 = 4cos^2theta

or 3/4 = cos^2theta

or costheta = √3/2

or theta = 30°.....(1)

Therefore, Sectheta + Cosectheta = Sec30° + Cosec30° = 2/√3 + 2

or 2+2√3/√3

or 2√3+6/3...... answer