Question

If 7tanA=4, then find the value of :
7SinA - 3CosA / 7 SinA + 3CosA​

Answer 1

Step-by-step explanation:

The answer for the question is 1/7..!!!!

Answer 2

Answer:

$\frac{1}{7}$

Step-by-step explanation:

$given \: \: 7 \tan(x) = 4 \\ \\ and \\ \\ \frac{7 \sin(x) - 3 \cos(x) }{7 \sin(x) + 3 \cos(x) } \\ \\ divide \: by \: cosx \\ \\ = \frac{ \frac{7 \sin(x) - 3 \cos(x) }{ \cos(x) } }{ \frac{7 \sin(x) + 3 \cos(x) }{ \cos(x) } } \\ \\ = \frac{7 \tan(x) - 3}{7 \tan(x) + 3 } \: \: \: \: since \: < \frac{ \sin(x) }{ \cos(x) } = \tan(x) > \\ \\ = \frac{4 - 3}{4 + 3} \\ \\ = \frac{1}{7}$

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