If 7th and 18th terms of an A.P. are 34 and 64 respectively, then its 18th term is?
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I think you have written the question in the wrong way
it's given the 18th term is 64
it's given the 18th term is 64
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7th term is 34
18th term is 64
a + 6d = 34......1
a + 17d = 64........2
1-2
a + 6d - a - 17d = 34-64
-11 d = -30
d = 30/11
a = 34/ 180/11 = 34×11/180
Substitute a and d in a + 17d
Then we get 64 as per the given question.
18th term is 64
a + 6d = 34......1
a + 17d = 64........2
1-2
a + 6d - a - 17d = 34-64
-11 d = -30
d = 30/11
a = 34/ 180/11 = 34×11/180
Substitute a and d in a + 17d
Then we get 64 as per the given question.
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