if 7th term and 13th term of an AP be 34 and 64 then find its 18th term
plzz solve this auestion step by step in proper way fast i will mark you as brainlist
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a+(n-1)d is the formula
7th term is 34 hence a+6d=34
13th term is 64 hence a + 12d =64
subtracting the two equations we get
6d=30 hence d =5
hence a=4
hence 18 th term is
4+(18-1)5=89
samson70:
plzz solve it properly then only i will mark you as brainlist
=> a+6d = 34------(1)
T13 = 64
=> a+12d = 64 ------(2)
On subtracting equation 1 from 2, we get
6d = 30
=> d = 5
a = 4
T18 = a+17d
= 4+ 17*5
= 4+85
= 89
a+12d=64
so
6d=30
d=5,a=4
then
18th term =4 +17*5=89
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