If 7th term of an
a.P is 1/9 and 9th term is 1/7, find 63rd term.
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10
Step-by-step explanation:
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Answered by
6
Step-by-step explanation:
a7=1/9
a+6d=1/9
a=1/9-6d
a9=1/7
a+8d=1/7
1/9-6d+8d=1/7
1/9+2d=1/7.
2d=1/7-1/9
2d=9-7/63
2d=2/63
d=1/63
so,
a=1/9-6d
a=1/9-6/63
a=7-6/63
a=1/63
now,
a63=a+62d
=1/63+62/63
=1+62/63
=63/63
=1
so, a63=1
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