Question

.If 7th term of an A.P.is1/9- and 9th term is 1/7
, find 63 term.​

Answer 1

Answer:63term is 1

Step-by-step explanation:

Given,

a+6d=1/9.........eqn 1

9a+54d=1........eqn2

a+8d=1/7...........eqn3

7a+56d=1..........eqn4

a+62d=?

Multiply eq.2 by 7 and eq.4 by 9.

We get,

63a+378d=7

63a+504d=9

____________

-126d=-2

d=1/63

Put d=1/63 in eq.1

a+6×1/63=1/9

a+6/63=1/9

a+2/21=1/9

21a+2=21/9

a=1/63

Put the value of a and d in a+62d to find the 63 term

=1/63+62×1/63

=1/63+62/63

=63/63

=1

So the 63rd term of an A.P. is 1