Question

If 7th term of an ap is 0 then prove that its 37th term is six times the 12th term

Answer 1

Answer:

Step-by-step explanation:

Solution attached in attachment.

Answer 2

Answer with Step-by-step explanation:

Since we have given that

7 th term of an AP = 0

So, it becomes,

$a_7=0\\\\a+6d=0\\\\a=-6d$

So, 37 th term would be

$a_{37}=a+36d=-6d+36d=30d$

and 12 th term would be

$a_{12}=a+11d=-6d+11d=5d$

So, we get that

$6\times 5d=30d\\\\6\times a_{12}=a_{37}$

Hence, proved.

# learn more:

If the 5th term of an ap is 0 then prove that 33rd term is 4 times its 12th term

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