Question

If 7th term of AP is 34
and 34th term is 64, then
its 18th term is?​

Answer 1

Answer:Let 1st term be "a" and common difference be "d" then 7 term and 13 term can be written as a+6d=34......equ.(1) a+12d=64......equ.(2) Solve both equ. We get a=4 & d=5 then So, 18 term be a+17d= 4+17 5 = 89

Step-by-step explanation: make me as brainlist

Answer 2

Answer:

$\large\boxed{\sf{\dfrac{416}{9}}}$

Step-by-step explanation:

Given an AP such that,

7th term = 34

34th term = 64

To find the 18th term.

Let the first term is a and common Difference is d

Therefore, we will get,

=> a + 6d = 34 .........(1)

=> a + 33d = 64 .......(2)

Subtracting eqn (1) from (2), we get

=> 33d - 6d = 64 - 34

=> 27d = 30

=> d = 30/27

=> d = 10/9

Substituting this value in (1), we get,

=> a + 6(10/9) = 34

=> a + 60/9 = 34

=> a = 34 - 60/9

=> a = 34 - 20/3

=> a = (102-20)/3

=> a = 82/3

Thus, we have,

=> 18th term = a + 17d

=> 18th term = 82/3 + 170/9

=> 18th term = (246+170)/9

=> 18th term = 416/9

Hence, 18th term is 416/9