If 7times the 7th term of an A. P is equal to 11times the 11th term. Show that is 18th term is zero. Can you find the first term and the common difference? Justify your answer
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Step-by-step explanation:
Atq
7(a+6d)=11(a+10d)
7a +42d=11a+110d
0=11a-7a+110-42d
0=4a+68d
0=4(a+17d)
0=a+17d(i)
Now
A18=a+(18-1)d
A18=a+17d
A18=0 by(i)
Hence proved
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