If 7x+6y=40 and 6x+7y=38 , then what is the value of (x-y)
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multiplying eq1 by 6 and eq2 by 7
so 42x+36y = 240
42x+49y = 266
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0 - 13y = -26
y = 2
and 7x+6×2 = 40
x = 4
so,, x-y = 4-2 = 2 ...ans.
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