Math, asked by comsysinfotech, 27 days ago

If 7x+6y=40 and 6x+7y=38 , then what is the value of (x-y)​

Answers

Answered by takpihu261
2

Answer:

2

Step-by-step explanation:

2 is the right answer of this question.

Attachments:
Answered by ydharmendra888
0

Answer:

2

Step-by-step explanation:

7x+6y=40--------(1)

6x+7y=38---------(2)

multiply by 6 in(1) and by 7 in(2) and subtract each other we get

42x+36y=240

42x+49y=266

- - -

____________

-13y = -26

y= -26/-13=2

put the value of y in the (1) we get

7x+6*2=40

7x+12=40

7x=40-12

7x=28

x=28/7=4

Now the value of (x-y)

(4-2)

=2

I think it is helpful for you

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