Question

If 7x3 —43x2 = 43x —7 has one zero 7, then find other two zeros (1) 1 , 1 7 (2) —1, −1 7 (3) —1, 1 7 (4) 1, −1​

Answer 1

Answer:

x=-1

x= 1/7 =0.143

STEP1:Equation at the end of step 1 ((7 • (x3)) - 43x2) - (43x - 7) = 0 STEP 2 :Equation at the end of step2: (7x3 - 43x2) - (43x - 7) = 0 STEP3:Checking for a perfect cube

 3.1    7x3-43x2-43x+7  is not a perfect cube

Trying to factor by pulling out :

 3.2      Factoring:  7x3-43x2-43x+7 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  -43x+7 

Group 2:  -43x2+7x3 

Pull out from each group separately :

Group 1:   (-43x+7) • (1) = (43x-7) • (-1)

Group 2:   (7x-43) • (x2)

Step-by-step explanation:

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