If 7y8 is exactly divisible by 3, then
the least value of y is
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For any number to be divisivle by 3, the sum of the digits must also be divisible by 3.
According to the question,
7+y+8 must be divisible by 3.
Therefore, 15+y must be divisible by 3.
Since, 15 is already divisible by 3, hence the least value of y is zero.
Hence the number will be 708.
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