Question

if 8*1/3% a no. is added with itself then the result becomes 520. find the original number.​

Answer 1

Answer:

answer is 480

Step-by-step explanation:

let the number be X then by putting in the equation we will get 480 as the answer

Answer 2

The original number = 480

Given :

8*1/3% a no. is added with itself then the result becomes 520

To find :

The original number

Solution :

Step 1 of 2 :

Form the equation to find the original number

Let the original number = n

By the given condition

$\displaystyle \sf n + \bigg(n \times \frac{ \frac{25}{3} }{100} \bigg) = 520$

Step 2 of 2 :

Find the original number

$\displaystyle \sf n + \bigg(n \times \frac{ \frac{25}{3} }{100} \bigg) = 520$

$\displaystyle \sf{ \implies }n + \bigg(n \times \frac{ 25 }{3 \times 100} \bigg) = 520$

$\displaystyle \sf{ \implies }n + \bigg(n \times \frac{ 1 }{3 \times 4} \bigg) = 520$

$\displaystyle \sf{ \implies }n + \frac{n}{12} = 520$

$\displaystyle \sf{ \implies } \frac{12n + n}{12} = 520$

$\displaystyle \sf{ \implies } \frac{13 n}{12} = 520$

$\displaystyle \sf{ \implies } n = 520 \times \frac{12}{13}$

$\displaystyle \sf{ \implies }n = 480$

Hence the required original number = 480

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