If (8/15)^3 - (1/3)^3 - (1/5)^3 = x/75, find x.
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Hi ,
*********************
We know that ,
If a + b + c = 0 then
a³ + b³ + c³ = 3abc
****************************
Here ,
Let a = 8/15 ,
b = - 1/3 ,
c = - 1/5 ,
a + b + c
= 8/15 - 1/3 + 1/5
= ( 8 - 5 - 3 ) / 15
= 0
Therefore ,
a + b + c = 0 ----( 1 )
Now ,
( 8/15 )³ + ( -1/3 )³ + ( - 1/5 )³ = x/75
3 ( 8/15 ) ( - 1/3 ) ( - 1/5 ) = x /75
After cancellation ,
8 = x
Therefore ,
x = 8
I hope this helps you.
: )
*********************
We know that ,
If a + b + c = 0 then
a³ + b³ + c³ = 3abc
****************************
Here ,
Let a = 8/15 ,
b = - 1/3 ,
c = - 1/5 ,
a + b + c
= 8/15 - 1/3 + 1/5
= ( 8 - 5 - 3 ) / 15
= 0
Therefore ,
a + b + c = 0 ----( 1 )
Now ,
( 8/15 )³ + ( -1/3 )³ + ( - 1/5 )³ = x/75
3 ( 8/15 ) ( - 1/3 ) ( - 1/5 ) = x /75
After cancellation ,
8 = x
Therefore ,
x = 8
I hope this helps you.
: )
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