Question

if 8+2+3 is equal to 497, 6+5+4 is equal to 376 then 7+2+9 is equal to ?​

Answer 1

Answer:

8+2+3 = 497.

where, 4= first digit divided by 2 =8/2 =4

9= first digit + 1 =8+1 =9

7=(9-4)+2 =5+2 =7

simillary,

6+5+4 = 376.

where, 3= first digit divided by 2 =6/2 =3

7 =first digit + 1 =6+1 =7

6= (7-3)+2 =4+2 =6

7+2+9 = 7/2 8 13/2

where, 1st=7/2

2nd= 7 + 1 =8

3rd= (8-7/2) +2 = 9/2 +2 =13/2

Answer 2

Given:

In the question we are given two equations where we have to find the third one based on the trick used in the given two as follows:

8+2+3 is equal to 497

6+5+4 is equal to 376

To Find:

We are required to find 7+2+9 is equal to?

Solution:

In the first equation given 8+2+3 = 497.

where"

The first digit of the number 497, 4 is found out by the following method:

The first digit 8 is divided by 2 =8/2 =4

The second digit 9 = first digit + 1

                               =8+1

                               =9

The third digit 7=(9-4)+2

                         =5+2

                         =7

Similarly, in the second equation

6+5+4 = 376.

where,

3= first digit divided by 2 =6/2 =3

7 =first digit + 1

  =6+1

  =7

6= (7-3)+2

 =4+2

 =6

So, to find out the third number we have to follow the same procedure:

where

The first digit is divided by 2 =7/2

The second digit  = first digit + 1

                             =7 + 1

                             =8

The third digit = (8-$\frac{7}{2}$) +2

                         = 9/2 +2

                         =13/2

Hence, the required answer is 7/2 8 13/2.

The equation so formed is 7+2+9 = 7/2 8 13/2

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