Question

If 8(2x-5) = 1 + 6(3x -7) , then x = ?

Answer 1

Ⲇⲛ⳽ⲱⲉⲅ

8(2x-5) = 1 + 6(3x -7)

16x-40 = 1+18x - 42

16x - 40 = 18x - 41

-40 + 41 = 18x - 16x

1 = 2x

1/2 = x

Thus , value of x is 1/2

Answer 2

Answer:

=> The value of x is $\frac{1}{2} .$

Step-by-step explanation:

Given that:-

$8(2x-5) = 1 + 6(3x -7)$

To find:- The value of x,

For solving this, we have to use the transposition method:  

As we have,

=> $8(2x-5) = 1 + 6(3x -7)$

Simplifying it further, we get

=> $(16x-40) = 1 + (18x -42)$

Subtract the numbers,

=> $(16x-40) = -41 + 18x$

Rearranging the terms,

=> $(16x-40) = 18x-41$

Add both sides by $40$,

=> $16x-40+40 = 18x-41+40$

Simplifying it further, we get

=> $16x= 18x-41+40$

=> $16x= 18x-1$

Subtract $18x$ from both sides,

=> $-2x = -1$

Divide both sides by $-2$,

=> $x = \frac{1}{2}$

Hence, the required solution is $\frac{1}{2} .$