Question

if (8.3)^x=(0.83)^y=100 then find the value of 1/x -1/y​

Answer 1

Answer:

1/2

Step-by-step explanation:

8.3^x =100

apply log on both sides

x log8.3 = log 10²=2

x= 2÷ log8.3

1/x = log 8.3 ÷2

0.83^y =100

apply log on both sides

ylog.83 = 2

y = 2÷ log.83

1/y = log.83 ÷2

1/x-1/y = (log 8.3 ÷2 )-( log.83 ÷2)

= (log 8.3-log 0.83)÷2

= log( 8.3/.83 )÷2

= log 10 /2

=1/2