if (-8,4),(2,4)and(5,a) collinear point then find the value of a
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a= 4
three points are said to be collinear, if they all lie in straight line..
also, the slope should be same..
slope = (y2-y1) / (x2-x1)
so, for eg., say if a= (-8,4) , b= (2,4) and c=(5,a)
ab = (4-4)/(2-4) = 0/-2 = 0
bc = (a-4/5-2) = (a-4)/3 = 0 (since slope is "0" for ab)
(a-4) = 0
a = 4
ac = (a-4)/(5+8) = 0 (since slope is "0" for ab)
a-4/13 = 0
a-4 = 0
a = 4
three points are said to be collinear, if they all lie in straight line..
also, the slope should be same..
slope = (y2-y1) / (x2-x1)
so, for eg., say if a= (-8,4) , b= (2,4) and c=(5,a)
ab = (4-4)/(2-4) = 0/-2 = 0
bc = (a-4/5-2) = (a-4)/3 = 0 (since slope is "0" for ab)
(a-4) = 0
a = 4
ac = (a-4)/(5+8) = 0 (since slope is "0" for ab)
a-4/13 = 0
a-4 = 0
a = 4
Answered by
0
Three points are said to be collinear, if they all lie in straight line..
slope of the line passing through the points is given by
slope = (y2-y1) / (x2-x1)
let us take the points a= (-8,4) , b= (2,4) and c=(5,a)
first finding the slope of the line passing through a and b
ab = (4-4)/(2-4)
= 0/-2
= 0
next finding the slope of the line passing through the points b and c
bc = (a-4/5-2) =
(a-4)/3
= 0 (since slope is "0" for ab)
so we have
(a-4) = 0
a = 4 (Adding 4 on both sides)
slope of the line passing through the points a and c is
ac = (a-4)/(5+8) = 0 (since slope is "0" for ab)
a-4/13 = 0
a-4 = 0
a = 4
slope of the line passing through the points is given by
slope = (y2-y1) / (x2-x1)
let us take the points a= (-8,4) , b= (2,4) and c=(5,a)
first finding the slope of the line passing through a and b
ab = (4-4)/(2-4)
= 0/-2
= 0
next finding the slope of the line passing through the points b and c
bc = (a-4/5-2) =
(a-4)/3
= 0 (since slope is "0" for ab)
so we have
(a-4) = 0
a = 4 (Adding 4 on both sides)
slope of the line passing through the points a and c is
ac = (a-4)/(5+8) = 0 (since slope is "0" for ab)
a-4/13 = 0
a-4 = 0
a = 4
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