Question

If 8.4 g of element x includes 9.03*10^22 atoms and 0.1 mol of x2y3 weights 16 g then atomic mass of y

Answer 1

Answer:

Explanation:

n of x = 9.03×10^22/6.02×10^23=0.15

Molar mass of x = 8.4/16=56g

Molar mass of compound = 16/0.1=160g

56×2+My×3=160

My=16g/mol

Relative Atomic Mass =16g

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