Question

If 8 cot teta =7, check wether (1+sin teta)(1-sin teta)/(1+cos teta)(1-cos teta)=cot^2 teta or not

Answer 1

Answer:

yes it is true.

$8 \cot( \alpha ) = 7 \\ = > \cot( \alpha ) = \frac{8}{7} \\ now \\ \\ \frac{1 + \sin( \alpha ) \times (1 - \sin( \alpha ) }{1 + \cos( \alpha ) {?}^{2} \times (1 - \cos( \alpha ) )} \\ = \frac{ {1}^{2} - { \sin( \alpha ) }^{2} }{ {1}^{2} - { \cos( \alpha ) }^{2} } \\ = \frac{ \cos( \alpha ) }{ { \sin( \alpha ) }^{2} } \\ = { \cot( \alpha ) }^{2}$

here I have written alpha in place of theta so , don't get confused.